位运算
2025-12-18 19:22
int a[]; a &= ~(1<<n); 变量a[n]设置为0,其他bit不变 a |= (1<<n); 变量a[n]设置为1,其他bit不变 将a[x2到x1]=0000 假如x1到x2共4个(包含x1)bit为置0,1111 == 0xf a &= ~(0xf << x1); 将a[x2到x